The perimeter of a rectangleis 12 inches. the width of the rectangle is 2 inches less than the length of the rectangle. find the dimensions of the rectangle

Side lengths 4 (length) and 2 (width) satisfy this word problem.

We see know that the perimeter of a rectangle is given by 2l+2w. If 2l+2w were to equal 12, 2l would have to be less than 6 (because 2(6) has already reached the perimeter limit). We can start testing values from there (keep in mind that your primary secondary side length must be 2 less than the primary one).

2(5)+2(3)=10+6=16 No
2(4)+2(2)=8+4=12 Yes
2(3)+2(1)=6+2=8 No

We see that side lengths 4 and 2 are the only sides that satisfy the perimeter.

:)

(x) - (y) = (1 + 4i)

(3 + 6i) - (2 + 2i) = (1 + 4i)