Ahexagon can be divided into how many triangles by drawing all of the diagonals from one vertex?
a. 4
b. 5
c. 6
d. 3

4 triangles are formed.

Step-by-step explanation:

Given a hexagon that can be divided into triangles by drawing all of the diagonals from one vertex.

we have to find the number of triangles formed.

As shown in attachment if we a diagonals from one vertex then only 3 diagonals are drawn which results into 4 triangles.

Hence, 4 triangles are formed by drawing all of the diagonals from one vertex.

Hence, option A is correct.

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west