What is the general form of the equation for the given circle centered at o(0, 0)?
a. x^2 + y^2 + 41 = 0
b. x^2 + y^2 − 41 = 0
c. x^2 + y^2 + x + y − 41 = 0
d. x^2 + y^2 + x − y − 41 = 0

Option B. x² + y²- 41 = 0

Step-by-step explanation:

We have to find the equation of a circle with center as (0, 0) and a point on circle is (4, 5).

Since standard equation of a circle is x² + y² = r² with origin(0, 0) as center.

radius r = √(4-0)²+(5-0)² = √(16+25) = √41

Therefore equation of the circle will be

x² + y² = 41

x² + y²- 41 = 0

Option B. is the correct option.

step-by-step explanation:

at each of the parallel lines adjacent angles are supplementary. the angles have special names identifying their positions with respect to the parallel lines and transversal. they are corresponding angles, alternate interior angles, or alternate exterior angles. an angles is congruent to its matched angle.