Mathematics, 28.08.2019 10:30 cbrewer37

The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. the center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

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The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. th...

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