Amanufacturing unit currently operates at 80 percent of its capacity. the profit function for the unit at the optimum output, x, is given by p(x) = -0.1x^2 + 80x − 60. if the function f(x) models the current capacity of the unit, the composite function giving the unit's current profit function is a. f(p(x))=-0.064x^2+6.4x-60 b. p(f(x))=-0.64x^2+0.64x-60 c. p(f(x))=-0.064x^2+64x-60 d. p(f(x))=-0.64x^2+6.4x-60 e. f(p(x))=-0.064x^2+64x-60 if the optimum output is 500 units, the current profit is $ a.15,400 b.15,940 c.16,060 d.16,600

Option D

Step-by-step explanation:

Let the manufacturing unit operates with the maximum capacity = x

Since manufacturing unit currently operates at 80%

So function f(x) that models the current capacity of the unit will be

f(x) = (0.80)x

Given profit function for the unit at optimum output is

p(x) = ( -0.1) x² + 80x - 60

so composite function giving the unit's current profit function will be

p[f(x)] = (-0.1) (0.8x)² + 80(0.80x) - 60

         = -(0.1) (0.64x²) + 80 (0.08x) - 60

         = - 0.64x² + 6.4x - 60

Option D will be the answer.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8