Mathematics, 16.01.2020 06:31 genyjoannerubiera
Find the critical numbers sin^2x+cosx 0 < x< 2pi
Answers: 2
![\bf sin^2(x)+cos(x)\iff [sin(x)]^2+cos(x)\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=2sin(x)cos(x)-sin(x)\implies 0=2sin(x)cos(x)-sin(x) \\\\\\ 0=sin(x)[2cos(x)-1]\implies \begin{cases} 0=sin(x)\\ sin^{-1}(0)=\measuredangle x\\ \pi \\ ----------\\ 0=2cos(x)-1\\\\ \frac{1}{2}=cos(x)\\\\ cos^{-1}\left( \frac{1}{2} \right)=\measuredangle x\\\\ \frac{\pi }{3},\frac{5\pi }{3} \end{cases}](/tpl/images/0457/3974/f098c.png)
Other questions on the subject: Mathematics
Mathematics, 21.06.2019 16:50, maxstmichel3868
For the equations below which statement is true ?
Answers: 2
Mathematics, 21.06.2019 23:10, kleighlamb4850
Which best describes the function on the graph? direct variation; k = −2 direct variation; k = -1/2 inverse variation; k = −2 inverse variation; k = -1/2
Answers: 2
You know the right answer?
Find the critical numbers sin^2x+cosx 0 < x< 2pi...
Questions in other subjects:
Mathematics, 28.07.2019 09:30
Chemistry, 28.07.2019 09:30
Mathematics, 28.07.2019 09:30
