Could you me?
the work of a student to solve the equation
2(5y − 2) = 12 + 6y is shown below:
step 1: 2(5y − 2) = 12 + 6y
step 2: 7y − 4 = 12 + 6y
step 3: y − 4 = 10
step 4: y = 14
step 5: y = 7
in which step did the student first make an error and what is the correct step? step 2: 7y − 4 = 6 + 3y
step 2: 10y − 4 = 12 + 6y
step 3: 5y − 2 = 2(10 + 3y)
step 3: 2(5y − 2) = 10 + 3y