F(x)=x^2-2x-8 what is axis of symmetry , vertex and roots?

X^2 - 2x - 8 

2 numbers that multiplied give -8
2 numbers that added give -2 

2 x -4 = -8
2 + -4 = -2

(x + 2) (x -4 )

roots equal = -2, 4
  

x^2 - 2x -8
  a.   b.   c          because b is -2 in the equation you don't plug b as a negative    
                            in the axis of symmetry
    
axis of symmetry = -b divide by 2a 

                               2 divide by 2(1) =1 

Vertex= (1, -9)

Ibelieve the answer would be 7, 13, 23