Mary has 18 coins with a total value of $2.85. if the coins are dimes and quarters, how many of each type of coins does mary have

Let's say x represents the number of dimes and y represents the number of quarters. 

Note: A dime is worth 10 cents and a quarter is worth 25 cents. Therefore, their coefficients would be 0.1 and 0.25 (you must divide them by 100, since 1 dollar = 100 cents). 

Now you can set up a system of equations and solve by substitution.

x + y = 18
0.1x + 0.25y = 2.85

In order to substitute, you have to solve for one of the variables in terms of the other. This will be easiest to do with the first equation.

x + y = 18
y = 18 - x

Now, substitute in that value of y into the second equation.

0.1x + 0.25(18 - x) = 2.85

Now, you can solve for x.

0.1x + 4.5 - 0.25x = 2.85
- 0.15x = -1.65
x = 11

You have 11 dimes.

Now you can substitute that value into your original first equation.

(11) + y = 18
y = 7

You have 7 quarters.

 11 dimes and 7 quarters

Ithink the answer is b