Which equation represents a circle with a center located at (-2,2) and a circumference of 16(pie)

First let's find the radius...

C=2πr

r=C/(2π)  and since C=16π

r=(16π)/(2π)=8

The standard form of the circle equation is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the location of the center of the circle so:

(x--2)^2+(y-2)^2=8^2

(x+2)^2+(y-2)^2=64