the product of two consecutive even integers is 48. which equation can be used to find these integers?
a. x^2=48
b. 2x+2=48
c. x^2+2x=48
d. x^2+x=48

Two consecutive even integers are:

x and x+2  the product of which is:

x(x+2) and we are told that this is equal to 48 so:

x(x+2)=48

x^2+2x=48 ← that is your answer...

x^2+2x-48=0

x^2+8x-6x-48=0

x(x+8)-6(x+8)=0

(x-6)(x+8)=0  so there are two solutions that satisfy the conditions of the question...

x=6 and x=-8 so the pair of numbers solutions is:

-8 and -6  and

6 and 8