Mathematics, 03.02.2020 18:56 maliyahsanmiguel

Plez i need this for homework now

the data sets show the years of the coins in two collections.

derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

paul's collection: 1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

find the indicated measures of center and the measures of variation for each data set. round your answer to the nearest hundredth, if necessary.

derek's

collection

paul's

collection
find the
mean
median
range
iqr
mad
for derek's collection and paul's collection

Answers: 1

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Answers

Answer from: adamske0

for Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

for Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

Derek's collection:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

$Mean=\dfrac{1950+1952+1908+1902+1955+1954+1901+1910}{8}\\\\\\Mean=\dfrac{15432}{8}\\\\\\Mean=1929$

Now absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

and the mean of these absolute deviation gives the MAD of the data i.e.

$MAD=\dfrac{21+23+21+27+26+25+28+19}{8}\\\\\\MAD=23.75$

Now, on arranging the data in increasing order we get:

1901 1902 1908 1910 1950 1952 1954 1955

The least value is: 1901

Maximum value is: 1955

Range is: Maximum value-Least value

Range=1955-1901

Range= 54

Also, the median lie between 1910 and 1950 and is calculated as:

$Median=\dfrac{1910+1950}{2}\\\\\\Median=\dfrac{3860}{2}\\\\\\Median=1930$

Also, the lower set of data is:

1901 1902 1908 1910

and the median of lower set of data also known as first quartile or lower quartile is:

$Q_1=\dfrac{1902+1908}{2}\\\\\\Q_1=\dfrac{3810}{2}\\\\\\Q_1=1905$

and upper set of data is:

1950 1952 1954 1955

and the median of upper set of data i.e. upper quartile or third quartile is:

$Q_3=\dfrac{1952+1954}{2}\\\\\\Q_3=\dfrac{3906}{2}\\\\\\Q_3=1953$

Hence, IQR is calculated as:

$IQR=Q_3-Q_1\\\\\\i.e.\\\\\\IQR=1953-1905\\\\\\IQR=48$

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

$Mean=\dfrac{1929+1935+1928+1930+1925+1932+1933+1920}{8}\\\\\\Mean=1929$

Now absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

$MAD=\dfrac{6+1+1+4+3+4+9}{8}\\\\\\MAD=\dfrac{28}{8}\\\\\\MAD=3.5$

Now, on arranging the data in increasing order we get:

1920 1925 1928 1929 1930 1932 1933 1935

Least value= 1920

Maximum value= 1935

Range= 15 ( Since, 1935-1920=15 )

The median lie between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920 1925 1928 1929

and median of lower set of data is the first quartile or upper quartile and is calculated as:

$Q_1=\dfrac{1925+1928}{2}\\\\\\Q_1=1926.5$

and the upper set of data is:

1930 1932 1933 1935

Hence, we get:

$Q_3=\dfrac{1932+1933}{2}\\\\\\Q_3=1932.5$

Hence, IQR is calculated as:

$IQR=Q_3-Q_1\\\\\\IQR=1932.5-1926.5\\\\\\IQR=6$

Answer from: Quest

right

step-by-step explanation:

Answer from: Quest

What is the diagram u didn't post that

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Plez i need this for homework now

the data sets show the years of the coins in two coll...