Which transformations will produce similar, but not congruent, figures?

select each correct answer.

a. square abcd is rotated 270° clockwise and then dilated by a scale factor of 13 to form square a"b"c"d" .
b. square abcd is reflected across the x-axis and then dilated by a scale factor of 2 to form square a"b"c"d" .
c. square abcd is translated 8 units right and 8 units up and then reflected across the y-axis to form square a"b"c"d"
d. square abcd is dilated by a scale factor of 45 and then translated 1 unit right to form square a"b"c"d"

Square ABCD is reflected across the x-axis and then dilated by a scale factor of 2 to form square A"B"C"D" .

Square ABCD is rotated 270° clockwise and then dilated by a scale factor of 13 to form square A"B"C"D" .

Square ABCD is dilated by a scale factor of 45 and then translated 1 unit right to form square A"B"C"D" .

Step-by-step explanation:

i took the test

22 and 22

step-by-step explanation:

10 plus 12 equals 22.

12 plus 10 also equals 22 because regardless of what order they're in, they're gonna equal the same thing.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!