Based on the table, which of the following is true?

the interquartile range for company a employees is 2 more than the interquartile range for company b employees.

the interquartile range for company a employees is 0.5 more than the interquartile range for company b employees.

the interquartile range for company a employees is 1 more than the interquartile range for company b employees.

the interquartile range for company a employees is 2.5 more than the interquartile range for company b employees.

Hey!

Hope this helps...

First we would re-arrange these 2 sets of numbers from least to greatest...

Table 1 (Original): 2,4,8,8,2,6,4,8,3

Table 2 (Original): 2,6,3,5,2,4,6,3,2

Table 1 (Re-Arranged): 2,2,3,4,4,6,8,8,8

Table 2 (Re-Arranged): 2,2,2,3,3,4,5,6,6

Now we want to find the MIDDLE NUMBER of both tables...

Table 1 (Middle Number): 4

Table 2 (Middle Number): 3

Now we have 4 tables the numbers on the left and right of 4 in Table 1, and the numbers on the left and the right of 3 on Table 2 (Do not include 3 nor 4 in those tables)

Table 1.1 (left of 4): 2,2,3,4

Table 1.2 (right of 4): 6,8,8,8

Table 2.1 (left of 3): 2,2,2,3

Table 2.2 (right of 3): 4,5,6,6

The numbers that are underlined and italicized are the numbers we have to find the average of...

Table 1.1 (avg): (2+3)/2 > 5/2 > 2.5

Table 1.2 (avg): (8+8)/2 > 16/2 > 8

Table 2.1 (avg): (2+2)/2 > 4/2 > 2

Table 2.2 (avg): (5+6)/2 > 11/2 > 5.5

IQR (Interquartile Range) of Table 1: 8 - 2.5 = 5.5

IQR of Table 2: 5.5 - 2 = 3.5

So the answer to your question is A.) The interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.

cosine

step-by-step explanation: