What are the removable discontinuities of the following function?
f(x)=x^2-36/x^3-36x

the removal discontinuity of the following function at x=-6 or x=6.

Step-by-step explanation:

Since discontinuity are at x=0 ,6 or -6.

After cancelling, it leaves you with for x≠0.

Therefore, x+6=0(or x=-6) , x-6=0(or x=6)  is a removal discontinuity of the following function.

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y