Drake wants to save $750 so that he can take a class on computer analysis for cars. the class is being held on various dates over the next several months. drake is planning to take the class 6 weeks from now, so he plans to save $125 each week. unfortunately, drake had to take out a little money from his savings in the 3rd week. after 4 weeks, drake has $470. he knows that he must adjust his plan in order to meet his goal. drake came up with the following options: option a: stay with saving the original amount each week but take the class a week later than originally planned. option b: increase the amount of money he saves each week by $15 from his original plan.
which of the following is a true statement?
a. only option a will allow him to meet his goal.
b. only option b will allow him to meet his goal.
c. both options a and b will allow him to meet his goal.
d. neither option a nor option b will allow him to meet his goal.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

include a picture of the drawing in order for me to

step-by-step explanation: