How does the volume of a square pyramid change if the base area is quadrupled and the height is reduced to 1/9 of its original size

The volume of a square pyramid is solved through the equation,
                                     V = Bh/3
where V is volume, B is the area of the base, and h is the height. When we substitute the new values to the equation,
                                     V = (4B)(h/9)/3
                                     V = (4/9)(Bh/3)
As seen in the equation above, the volume is multiplied by 4/9. 

The third and fourth box.

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