Mathematics, 25.10.2019 14:43 edmistontrace53

21 ! the height of a projectile can be described as follows
y = −16t^2 + v0t + h0

where t=time in seconds;
y= height in feet
v0=initial velocity
h0=initial height
what would be the maximum height for a squirrel that jumped from a branch that was 10 ft off the ground with an initial velocity of 12 ft/s.

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21 ! the height of a projectile can be described as follows
y = −16t^2 + v0t + h0

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