Mathematics, 30.01.2020 19:59 juliajaelyn9658

sam is planning a 1748-mile driving trip. his car gets an average of 38 mpg, and the cost of gas is about $4.12/gallon. what is the approximate driving cost of the trip?

a. $172.48

b. $189.52

c. $194.26

d. $198.58

Answers: 2

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Answers

Answer from: LillianMRucker

B. $189.52

Step-by-step explanation:

The car run in 1 gallon of gas = 38 miles

To travel 1 mile distance, the consumption of gas by car = $\frac{1}{38}$ gallon

To travel 1748 miles distance, the consumption of gas by car = $1748\times\frac{1}{38}$ =46 gallons

Since, the cost of 1 gallon of gas = $4.12

Now, the cost of 46 gallons of gas = $4.12\times46=\$189.52$

Hence, the approximate driving cost of the trip = $189.52.

Answer from: Quest

5. y=6; de=7; fg=8

6. x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

y = 6

of course, the total chord length is the sum of the lengths of its segments.

de = dh +eh = 3+4 = 7

fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

x = lk = mk×nk/jk = 6×7/10 = 4.2

jl = jk +lk = 10 +4.2 = 14.2

mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

Find the value of the variable and the length of each chord for #5 and #6.

Answer from: Quest

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

In this figure,afc=efc . which statement is true by cpctc?

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