![\bf 2tan(\theta)+5=0\implies 2tan(\theta)=-5\implies tan(\theta)=-\cfrac{5}{2} \\\\\\ tan^{-1}[tan(\theta)]=tan^{-1}\left( -\cfrac{5}{2} \right)\implies \measuredangle \theta=tan^{-1}\left( -\cfrac{5}{2} \right)](/tpl/images/0452/8503/981db.png)
2tanθ+5=0
use a calculator to solve the following equation on the interval 0 less than or equa...
Mathematics, 13.01.2020 11:31 dirtridersteve65
2tanθ+5=0
use a calculator to solve the following equation on the interval 0 less than or equals theta less than 2 pi0≤θ< 2π.
Answers: 2
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