Acircle is centered at (3, 8) and is tangent to the x-axis. write its equation in standard form.

Step-by-step explanation:

We have been given that a circle is centered at (3, 8) and is tangent to the x-axis.

We know that the equation of  a circle in standard form is in format: , where,

= Coordinates of center of circle,

= Radius of circle.

Since x-axis is tangent to our given circle, so the radius of our circle will be 8 units as the radius of a circle is segment that connects the center of a circle with its perimeter. Since y-coordinate of our center is 8, this means the radius of circle is 8 units from the tangent line that is x-axis.

Upon substituting our given values in standard form of circle we will get,

Therefore, the equation of our given circle in standard form would be .

the two may have that, even a breakdown is probably offered

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²