Recall that the equation for horizontal distance "h" in feet of a projectile with initial velocity v0 and initial angle theta is given by h=(v0^2/16)sin theta cos theta. a.) assume the initial velocity is 60 (feet/second). what initial angle will you need to ensure that the horizontal distance will be exactly 100 feet? b.) assume the initial velocity is 60 feet/second. what is the maximum horizontal distance possible and at what angle does this occur?

A). 31.43°

B). 225 feet

Step-by-step explanation:

A) From the given equation for horizontal distance h of a projectile is given by

If initial velocity v0 = 60 ft/sec and horizontal distance = 100 feet

Then the equation will be

B). If v0 = 60 feet per second

Then we have to calculate the maximum horizontal distance and angle.

Since we know to cover the maximum distance in a projectile motion an object should be thrown at 45°.

Therefore the equation formed will be

h = 112.5 feet

linearly: 8560 bacteria

exponentially: approximately 75233 bacteria

step-by-step explanation:

assuming it is not exponential (we would have some really complicated logarithms), let's say it is linear. then, after 5 hours, it increased by 1200 bacteria, so every hour it increases by 240 bacteria. this means that after 19 hours, we get 19 * 240 + 4000 bacteria or 3800 + 760 + 4000 = 7800 + 760 = 8560 bacteria.

because it says round your answer, i will do this exponentially (with a calculator, of course). first, we need to find how much it multiplies by every hour, by taking the 5th root of 52/40 or 13/10. this is approximately 0.167. we still need to add 1 to this, because we are multiplying by that number, not adding that amount of the number. now, we just calculate 4000 * (1.167)^19. use a calculator to get approximately 75232.6, or 75233.

answer: ok

step-by-step explanation: