The function, f(x) = –2x2 + x + 5, is in standard form. the quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. the discriminate b2 – 4ac is 41. now, complete step 5 to solve for the zeros of the quadratic function. 5. solve using the quadratic formula. x = what are the zeros of the function f(x) = x + 5 – 2x2? x = x = x = x =

A quadratic equation   ....[1] where, a, b and c are coefficient then;

the solution fore this equation we have;

        ....[2]

Given the function in the standard form:

The quadratic equation is:

On comparing with equation [1] we have;

a = -2 , b = 1 and c = 5.

The discriminant is given by:

then;

Solve for the zeros of the quadratic function:

Substitute the given values in [1] we have;

then;

and

⇒ and

Therefore, the zeros of the given  function are:

,

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk