Mathematics, 04.01.2020 02:31 coolman5999alt
Solving systems of equations : how do i solve these when 1 doesn't have an x and 2 doesn't have a y.
1. 4x+y< 2
y> -2
2. x (greater then or equal to) -3
Answers: 1
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Solve each quadratic equation by factoring and using the zero product property. 10x + 6 = -2x^2 -2
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Rewrite the expression in z to the n power. the expression i was given is: 1 over z to the negative 1 half power.
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