State the coordinates of the reflection of the isosceles trapezoid across the line of reflection y = –x.
a=
b=
c=
d=

A' (-4,3)

B' (-4,1)

C' (-1,-1)

D' (-1,5)

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204