Find the solution set
a^2-8a+12=0
separate the two values with a comma

A^2-8a+12=0  (this is of the form ax^2+bx+c)

find jk=ac=12 and j+k=b=-8,   then  j and k must be -2 and -6

now replace -8a with -2a and -6a

a^2-2a-6a+12=0  now factor 1st and 2nd pair of terms...

a(a-2)-6(a-2)=0  which is equal to

(a-6)(a-2)=0

So a=(2, 6)

The full question isn’t shown. part of it is cut off