Idon't know to get the interval notation

(x^2+3)/(4x)≥1  multiply both sides by 4x

x^2+3≥4x  subtract 4x from both sides...

x^2-4x+3≥0  factor left side...

(x-1)(x-3)≥0  for this to be true both terms need to be positive or both terms need to be negative or either one of them are equal to zero. 

x≥3 and x≤1 thus the interval is

x=(-oo, 1], [3, +oo)

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)