Iknow i already asked this but this time it is 50 points
c=ax-bx
joseph claims that if a, b, and c are non-negative integers, then the equation has exactly one solution for x. select all cases that show joseph's claim is incorrect.

a. a-b=1,c=0
b. a=b, c≠0
c. a=b, c=0
d. a-b=1,c≠1
e. a≠b, c=0

Expression: c = ax - bx
Take x as a common factor, 
c = x(a - b)

when a=b, & c≠0 then equation won't balance, means claim is incorrect in this situation.
Again, If a≠b then equation won't balance, means claim is incorrect.

In short, Your Answer would be: Option B & E

Hope this helps!

The right answers are: option 2, option 3, option 4 and option 5.

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*