How do you find the slope for 6x=8y+10

6x=8y+10

Well you must first get your equation set up into the form called "Slope intercept." 
6x=8y+10
Add 8y on both of your sides because your y is suppose to be alone.
8y + 6x = 10
Subtract 6x on both sides since it is in fact the opposite of addition.
8y = 6x + 10
Now, you will divide by 8 on both sides. When doing this your y will be alone.
y= 6/8x + 10/8
Note: You can leave it like this but you want to probably simplify.
y = 3/4x + 5/2
       or
y = 3/4x + 2 1/5

THERE YA GO BUDDY! :D

-Gives you a thumbs up-

In order to find the slope, we must first convert the general function into standard linear form, which is y=mx+b. In order to do this, subtract 8y from both sides to get 6x-8y=10. Then, subtract 6x from both sides to get -8y=-6x+10. Now we must get y by itself, so we divide both sides by -8 to get y=3/4x-1.25.

Now, from the standard linear form, we can derive that the slope is 3/4.

That they are numbers and related to each other.