For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year. the value, v(t), of $384,000 worth of assets after t years, that depreciate at 16% per year, is given by the formula v(t) = vo(b)t. what is the value of vo and b, and when rounded to the nearest cent, what are the assets valued at after 7 years?

Worth of assets after 7 years will be $113314.70

Step-by-step explanation:

The value V(t) of asset after t years is given by the formula

In the formula given V(t) = Worth of asset after t years

and is the initial value of the assets.

Since rate of depreciation of the assets is = 16% per year

So by the given formula

b = (1 - 0.16)

b = 0.84

Now we have to calculate the value of assets worth $384000 after 7 years.

By the given formula

= 384000(0.295)

= $113314.70

Therefore, worth of assets after 7 years will be $113314.70.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents