Factor 4x^3-16x^2+12-3x

4x^3-16x^2+12-3x
Rearrange: (4x^3-16x^2)-(3x+12)
Factor out GCF : 4x^2(x-4)-3(x-4)
(4x^2-3)(x-4)
I hope this helped! :)

4x^3-16x^2-3x+12
first you would have to find the GFC but there is none.
since there are 4 terms in this equation you have to group the numbers.
In 4x^3-16x^2 the GCf is 4x^2 and in -3x+12 the GCF is -3
4x^3-16x^2-3x+12
=4x^2(x-4)-3(x-4)
when your finding the GCF you are practically dividing you GCF with the 2 terms that were in common. that is how i got (x-4). you would keep your GCF in the front of you equation like so, 4x^2(x-4)-3(x-4).

later you would take the numbers outside of the bracket and combine them, leading you to (4x^2-3) with (x-4)
therefore your answer would be (4x^2-3)(x-4)
4x^3-16x^2-3x+12
=4x^2(x-4)-3(x-4)
=(4x^2-3)(x-4)
because both (x-4)'s are the same and so are the signs, you do not need to square it or put two of the terms together like this, (4x^2-3)(x-4)(x-4). since they are both the same you leave one out.

What’s the improper fraction?

Can u send a screenshot of it? !