Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. how many pounds of the more expensive candy are needed to produce a 15-pound mixture that sells for $7.00 per pound?

5
6
9
10

5 Pounds

Step-by-step explanation:

Let A represent the number of pounds of $6 candy

Let B represent the number of pounds of $9 candy

Therefore ,

A + B = 15

A= 15 - B

6 × A + 9 × B = 15 × 7

6A + 9B = 105

In order to find B we substitute 15-B for A in the equation.

6 x (15 - B ) + 9B = 105

90 - 6B + 9B = 105

3B = 105 - 90

3B = 15

B = 5

To solve for A

A = 15 - B

Where B is 5

A = 15 - 5

A = 10

From the calculation,

Number of pounds of $6 per pound candy is 10 and the number of pounds of the $9 per pound candy is 5.

Therefore, since B is representing the number of pounds of the $9 candy , and it is the most expensive, then 5 pounds of the more expensive candy are needed to produce a 15-pound mixture that sells for $7.00 per pound.

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.