Paula bought 8 pairs of socks. she paid $104.the other pairs each cost the same amount. two pairs of socks each cost $16. how much did each of the other pairs of socks cost?

Let's call the cost of one pair of the two pairs of socks that cost the same: x. We can call the cost of one pair of the other 6 pairs that cost the same: y. We can set up an algebraic equation:

2x+6y=104.

We are given that x=16, so we can substitute.

32+6y=104.

Subtracting 32 from both sides gives us

6y=72

y=12.

Each of the other pairs of socks cost $12.

It would be 15 m how i got the answer: (20x20) + b^2 = (25x25)400 + b^2 = 625625-400=225square that and get 15hope this : )

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