How can you express (9 + 36) as a multiple of a sum of whole numbers with no common factor?
a.) 1 × (9 + 36)
b.) 3 × (3 + 12)
c.) 6 × (3 + 6)
d.) 9 × (1 + 4)

The best answer here is D. 9 x (1 + 4) because all you have to do for this problem is factor. I know the wording makes it look like a confusing problem, but all you have to do is factor. 

The work is below:

(9 + 36)   Do not add these numbers together.

Pull out 9 from both terms because 9 is the GCF of both terms. This will help you factor it to the simplest form. 

(9 + 36) 

9/9 = 1

36/9 = 4

After pulling out the 9, the answer should look like: 

9 (1 + 4)

He is right i did this thing before