Figure abcd is a parallelogram.

which sequence could be used to prove that ad = bc?

first prove abc is congruent to cda, and then state ad and bc are corresponding sides of the triangles.

first prove abc is similar to cda, and then state ad and bc are opposite sides of the parallelograms.

first prove abcd is congruent to cdab, and then state ad and bc are corresponding sides of two parallelograms.

first prove abcd is similar to cdab, and then state ad and bc are opposite sides of the parallelograms.

quickly

First prove ABC is congruent to CDA, and then state AD and BC are corresponding sides of the triangles.

Step-by-step explanation:

In the given picture, we have a parallelogram ABCD with diagonal AC..

AB║ CD, AD║BC

Now, By its diagonal AC it is divided in two triangles Δ ABC and  Δ ADC

∠ACB=∠DAC  and ∠CAB=∠ACD  [alternate interior angles]

AC=AC  {Reflexive property}

∴ By ASA postulate of congruence ,

Δ ABC ≅  Δ ADC

⇒ AD = BC [corresponding sides of the congruent triangles are congruent]

Hence, The sequence could be used to prove that AD = BC is

"First prove ABC is congruent to CDA, and then state AD and BC are corresponding sides of the triangles. "

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.