Construct a polynomial function with the following properties: fifth degree, 5 is a zero of multiplicity 4, −4 is the only other zero, leading coefficient is 5

[tex]p(x)=5(x-5)^4(x+4)[\tex]

Step-by-step explanation:

If an nth order  polynomial P(x) has a zero, say w, then P(x) can be written as P(x)=(x-w)Q(x) for some Q(x) , a polynomial of degree (n-1). So, 5 is a zero with multiplicity 4, then {tex]P(x)=(x-5)^4 Q(x) [\tex} for some Q(x). -4 is the only other zero, so (x-(-4))=(x+4) is a factor of Q(x). P(x) is of fifth degree , so we have exhausted the possibilities to [tex]p(x)=(x-5)^4(x+4)R(x)[\tex] where R(x) is of degree 0 or a constant. But the leading coefficient is 5, so is the answer.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.