How much kinetic energy does an 80kg man have while running at 1.5 m/s?

KE = 1/2mv^2
so
KE = 1/2(80)(1.5)^2
= 40×2.25
= 90J, I believe the answer is

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4