If data set a has a larger standard deviation than data set b, data set a is less spread out than data set b

The given statement is false.

Step-by-step explanation:

Given that there are two data sets A and B. data set A has a larger std deviation

Standard deviation is nothing but the square root of variance

Variance is the sum of squares of deviations of each entry from the mean.

Hence larger the std deviation larger is the spread

Since data set A has a larger standard deviation, the statement

Data set A is less spread out than Data set B is false.

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function