An empty 6-gal water jug weighs 0.5 lb. with 3 c of water inside, the jug weighs 2 lb. which equation models the jug’s weight y when it contains x cups of water?

The equation can be modeled be : y = 0.5 + 0.5 × x

Step-by-step explanation:

Weight of empty 6-gal water jug = 0.5 lb

After filling 3 cups of water inside, the weight of jug becomes 2 lb

So, increased weight after filling 3 cups of water = 1.5 lb

So, weight of 1 cup of water = 0.5 lb

Now, weight of the jug be y and water filled be x cups

Hence, The equation can be modeled be :

y = 0.5 + 0.5 × x

Thus, this is our required equation.

answer: re

step-by-step explanation: idk buddy

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75