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Mathematics
, 12.12.2019 01:31
jahnoibenjamin
Need will do anything
use the substitution method.
{j+k=3
{j-k=7
there are an infinite number of solutions.
there is no solution.
the solution is (5, −2).
the solution is (8, 1).
Answers: 3
Show answers
Answers
Answer from:
QueenNerdy889
j+k=3
j-k=7
j-k+k=7+k
j = 7+k
7+k+k=3
7+ 2k = 3
7-7 +2k = 3 -7
2k = -4
2k/2 = -4/2
k = -2
j + -2 = 3
j+ -2 +2 = 3+2
j = 5
Check
5 + -2 = 3
3=3
The solution is (5, −2).
Answer from: Quest
, ; dcbsdkmnld
step-by-step explanation:
Answer from: Quest
where are the options?
step-by-step explanation:
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You know the right answer?
Need will do anything
use the substitution method.
{j+k=3
{j-k=7
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