 , 06.01.2020 20:31 donterriuscollier

# Find two consecutive integers such that seven times the first equals six times the second Odd integers are always one more that an even integer:
1st: 2n+1
2nd: 2n+3

EQUATION:
7(2n+1) = 5(2n+3)

14n+7 = 10n+15
4n = 8
n = 2

1st: 2n+1 = 5
2nd: 2n+3 = 7 step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5) step-by-step explanation:  ### Other questions on the subject: Mathematics Mathematics, 21.06.2019 19:00, Hazy095
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Find two consecutive integers such that seven times the first equals six times the second...

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