x2+y2−12x+6y−19=0
what is the center of the circle?
Mathematics, 29.11.2019 01:31 anna40794
The equation for the circle is:
x2+y2−12x+6y−19=0
what is the center of the circle?
(-6, 3)
(12, -6)
(6, -3)
(-12, 6)
Answers: 3
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You know the right answer?
The equation for the circle is:
x2+y2−12x+6y−19=0
what is the center of the circle?
x2+y2−12x+6y−19=0
what is the center of the circle?
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