Asap will give ! and 50 points
the table shows the results of four surveys that randomly sampled 50 families in a town about the number of pets their family has.
0 pets 1 pet 2 or more pets total
survey 1 12 13 25 50
survey 2 20 21 9 50
survey 3 10 13 27 50
survey 4 11 12 27 50
identify surveys that are likely biased. based on the unbiased surveys, what percent of the families in the town are expected to have 2 or more pets?
40 %
44 %
53 %
59 %

C. 53%

Step-by-step explanation:

From the table, we see that,

The number of families in Survey 1, 3 and 4 are increasing as the number of pets increases.

But, that is not happening in Survey 2. This might be due to some bias.

Thus, Survey 2 is most likely to be biased.

So, we get the unbiased survey are 1, 3 and 4.

So, the number of families in these surveys having 2 or more pets are,

Survey 1 = 25,        Survey 3 =  27,          Survey 4 = 27

So, the total number of families having 2 or more pets = 25 + 27 + 27 = 79

Also, the total number of families for the 3 surveys = 50 + 50 + 50 = 150

Thus, the percent of families having 2 or more pets = = 52.7% ≈ 53%

Hence, option C is correct.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10