Mathematics, 28.01.2020 03:31 nschavez123

Astop sign is in the shape of a regular octagon. a regular octagon can be created using eight triangles of equal area. one triangle that makes up the stop sign has a base of 20 inches and a height of 24 inches. calculate the area of the stop sign

a. 1400 sq. in

c. 1980 sq. in

b. 1920 sq. in

d. 1700 sq. in

Answers: 2

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Answers

Answer from: tshepi5348

The correct answer is b. $1920(in)^{2}$

Step-by-step explanation:

We know that the stop sign is in the shape of a regular octagon. Also, a regular octagon can be created using eight triangles of equal area.

We have the dimensions of one of this triangles. One triangle has a base of 20 inches and a height of 24 inches.

Wherever we have a triangle of base '''' and height '''' we can calculate its area using the following equation :

$area=\frac{(b).(h)}{2}$ (I)

The area of one of this triangles using the equation (I) is :

$area=\frac{(20in).(24in)}{2}=240(in)^{2}$

To obtain the area of the stop sign we need to multiply the area of one single triangle by 8 (because a regular octagon can be created using eight triangles of equal area) ⇒

$area_{StopSign}=8.(240in^{2})=1920(in)^{2}$

We found out that the correct answer is b. $1920(in)^{2}$

Answer from: carolinagarciap8kgmi

The correct answer is b. $1920(in)^{2}$

Step-by-step explanation:

We know that the stop sign is in the shape of a regular octagon. Also, a regular octagon can be created using eight triangles of equal area.

We have the dimensions of one of this triangles. One triangle has a base of 20 inches and a height of 24 inches.

Wherever we have a triangle of base '''' and height '''' we can calculate its area using the following equation :

$area=\frac{(b).(h)}{2}$ (I)

The area of one of this triangles using the equation (I) is :

$area=\frac{(20in).(24in)}{2}=240(in)^{2}$

To obtain the area of the stop sign we need to multiply the area of one single triangle by 8 (because a regular octagon can be created using eight triangles of equal area) ⇒

$area_{StopSign}=8.(240in^{2})=1920(in)^{2}$

We found out that the correct answer is b. $1920(in)^{2}$

Answer from: Quest

mr. flanders’ class sold 47 doughnuts and mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

$\left\{\begin{array}{l}x+y=85\\1.35x+1.08y=104.49\end{array}\right.\rightarrow \left\{\begin{array}{l}x=85-y\\1.35(85-y)+1.08y=104.49\end{array}\right.$