What is the solution to the compound inequality 5x + 7 > −8 and 3x + 7 ≤ 19?
x ≤ −3 and x ≥ 4
−3 ≤ x < 4
x > −3 and x ≥ 4
−3 < x ≤ 4

Solve each

5x+7>-8
minus 7 both sides
5x>-15
divide by 5
x>-3

3x+7≤19
minus 7 both sides
3x≤12
divide by 3
x≤4

so we got
x>-3 AND x≤4
and means that the solution set must satisfy both at once
so x is bigger than -3 and less than or equal to 4
so between -3 and 4 including 4
-3<x≤4

last one