Asmall plane is 20 miles due north of the airport. a jet at the same altitude as the plane is 64.5 miles west of the airport. to the nearest tenth, what is the distance between the small plane and the jet? enter your answer as a decimal in the box.

Distance between the small plane and the jet is 67.52 miles.

Step-by-step explanation:

Since we have given that

Distance traveled by the small plane to the north of the airport = 20 miles

Distance traveled by the jet to the west of the airport = 64.5 miles

We need to find the distance between the small plane and the jet.

Since it forms "Right angled triangle " as shown in the figure.

Hence, Distance between the small plane and the jet is 67.52 miles.

answer: the answer is 40.82

step-by-step explanation: 3.14 x 13(or half of 26) to the power of 2

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13