Solve the system by the elimination method. check your work.
x - 3y = 0
3y - 6 = 2x

X - 3y=0
3y - 6 =2x
__________
x - 3y=0 ........(1)
-2x + 3y=6 ........(2)
__________
-x = 6 ==》x = -6 .........(3) subst. in (2)

-2 (-6) + 3y = 6 ==》3y= -6 ==》y = -2

(-6,-2)

Explanation:
The elimination method calls for two variables that cancel each other out. 
In this circumstance, you already have 3y and -3y.

First, make the orders of the equations the same. I got the x's to the same side on each equation.
This left me with:
x=3y        2x=3y-6.
Now, subtract the first equation from the second one to get x=-6.
That's the first part of the solution. For the y, you can just plug x into one of the equations and solve. I'll use the first one. 
-6-3y=0.    
Now get the ys to one side: -6=3y. Divide both sides by 3 to get y= -2.
Now that you have an x and a y coordinate, your solution is (-6,-2).

To check: plug both values in for their variables into each equation.
3(-2)-6=2(-6)   solve to get... -12=-12, which is true, meaning the solution works for that equation.

-6-3(-2)=0   solve to get... 0=0. The solution works for both equations.