Aspinner with 10 equal-sized sections numbered 1 to 10 is spun once. what is the probability that the spinner will land on a number that is not a multiple of three?

First, we should find all the multiples of 3 from 1 to 10
3*1=3
3*2=6
3*3=9

So then we know there are 3 multiples of 3 from 1 to 10. Then there must be 7 numbers that aren't multiples of 3 (10-3=7)

Then to find probability, we do the part divided by the whole
7/10 is the final answer

Hope this helps

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