a city manager wants to add a playground in a new city park. the rectangle below represents the plan for the dimensions of the rectangular playground.
w
x + 15

a. find the width (w) of the rectangle if the area of the rectangle is x2 + 18x + 45.
area= x2 +18x+45

b. find the dimensions (length × width) and the area of the playground if x = 8 yards.

A. You are told that the length equals (x + 15), which means that you must factorise the area in order to find the width:
45 ÷ 15 = 3
(x + 15)(x + 3)
So the width is x + 3

b. Now you substitute in the value of x into both brackets, so
length: (x + 15) = (8 + 15) = 23 yards
width: (x + 3) = (8 + 3) = 11 yards

I hope this helps!

The academic affairs council is the highest expert body processing academic affairs, as stipulated by the university statutes. specialist aaro häkkinen (educational policy) took part in the council’s meeting. the agenda of the meeting included bachelors’ feedback, the timing of pedagogical studies, the grant system for tuition fees, the standardisation of administrative practices for internships and the situation of foreign-language and multilingual master’s programmes.