At what temperature will 0.0100 mole of argon gas have a volume of 275 ml at 100.0 kpa?

The main formula is 
PxV = nx RxT
P: pressure=100.0 Kpa, and 1 atm = 101.325 kilopascal (kPa), so 100Kpa=0.9atm
V :volume=0.275l
n: number of moles= 0.0100mole
R: Gas constant=8.31
T: temperature

so T = PxV /nx R=0.9 x0.275 / 0.01 x8.31=2.97°, so T=2.97°+273=275.97K

The only number less than 8 that can equal 12 would be 6, 36 is the dividend